What this move does
If you can translate, rotate and reflect a triangle, and then enlarge or shrink it, so that it fits exactly on another one, the two triangles are similar. The scale factor is called the ratio of similarity. Congruence is similarity with .
Proving similarity takes less than proving congruence: scaling does not change angles, so two pairs of equal angles are enough (AA). There are also “two sides in proportion and the included angles equal” (SAS) and “all three sides in proportion” (SSS).
Solving with similar triangles takes three steps:
- Find a pair of triangles with the same shape. The most common sources: parallel lines (the “A shape” and the “hourglass”), a shared angle, a right angle plus one more equal angle.
- Line up the corresponding vertices in the similarity statement, then write the proportions by position.
- Algebra: in a proportion, knowing three quantities gives you the fourth; for areas, use .
Predict first
Every side of a triangle is enlarged to times its length. How many times bigger is the area?
The base becomes times as long and so does the height, so becomes times as big. On the workbench above, drag “Scale” to and the area reading is ; drag it to and you get .
Work through one
Move △ABC onto △A′B′C′: one extra step, scaling
Step 1 / 4- Compare the sizes
Both triangles go the same way round, so no reflection is needed. But the dashed triangle is clearly bigger: with translation and rotation alone, the corresponding vertices will never line up.
The most common source: parallel lines
In draw a line parallel to . Then (corresponding angles) and is shared, so .
Example: DE ∥ BC, AD = 4, DB = 6, BC = 15. Find DE
Step 1 / 4- Find the similar triangles
, so (the small orange triangle and the whole big triangle).
When it fails
Break it
Counterexample lab: remove one condition
Conclusion: ← still true?
follows , so always stays parallel to .
Now you can drag on its own. First make clearly not parallel to and look at the three ratios. Then try to make by moving only.
As soon as those two ratios are equal, the “parallel” light comes on as well: implies . This is how you prove lines parallel using proportions. But be careful: alone does not imply parallel. That is “side-side-angle”, and can have two positions.
Practice
with ratio of similarity . The area of is . Find the area of .
In , lies on and on with . Given , and , find the length of .
In trapezoid , , , , and the diagonals and meet at . The area of is . Find the area of .
In , and at . Given and , find the length of .