What this move does
Two triangles are congruent if one of them can be moved by translation, rotation and reflection until it lies exactly on the other. Vertices that land on each other are called corresponding vertices; corresponding sides are equal and corresponding angles are equal.
A triangle has six measurements: three sides and three angles. The congruence criteria say you do not need to check all six. The right three are enough:
To prove two triangles congruent, follow three steps:
- Find the correspondence: imagine moving one triangle onto the other. Which vertex lands on which? Write corresponding vertices in the same positions.
- Collect three conditions: what you are given, a shared side, vertical angles, equal angles from parallel lines… Put together one of the five criteria above. Watch out: in SAS the angle must be the included angle, between the two sides.
- Read off the conclusion in order: the corresponding sides and angles you get from the congruence are read off by letter position.
The workbench above is practice for step 1. Look at the “Direction A→B→C” reading: does go clockwise or counterclockwise? Translation and rotation never change the direction; only a reflection does.
Predict first
Two triangles are congruent. In one, the vertices go counterclockwise; in the other, the corresponding vertices go clockwise. Can you make them coincide using only translations and rotations (no reflection)?
No. Translations and rotations slide the triangle around in the plane, so the direction stays the same. A reflection flips the piece of paper over and reverses the direction. If the directions differ, the corresponding vertices can only coincide after an odd number of reflections. So there are really two kinds of congruence: “slide it and it fits” and “you must flip it over first”. The mirror-symmetric figures that are common in geometry problems are of the second kind.
Work through one
Move △ABC onto △A′B′C′
Step 1 / 4- Check the direction first
The solid triangle goes counterclockwise; the dashed triangle goes clockwise. The directions are opposite, so this move needs one reflection.
Now an example on paper. Watch the pattern “find the correspondence → collect conditions → read off the conclusion”.
Example: AB = AD and CB = CD. Prove that AC bisects ∠BAD
Step 1 / 3- Find the correspondence
The diagonal splits quadrilateral into and . Fold along and should land on : the correspondence is , , .
When it fails
Break it
Counterexample lab: remove one condition
Conclusion: Two triangles with two sides and one angle equal are congruent ← still true?
Fix and , and then choose the other side of this angle. Drag the slider: each value of gives exactly one triangle.
Again and , but now the third condition is the side opposite : . Draw an arc with center and radius ; wherever it meets the ray is a possible . Drag from small to large and count the crossing points.
- : the arc cannot reach the ray, so there is no triangle.
- : the arc touches the ray, so there is exactly one, and is a right angle. This is why HL works.
- : two crossing points, giving an obtuse triangle and an acute one. They have the same two sides and the same opposite angle, but they are not congruent.
- : back to just one.
So “side-side-angle” is not a congruence criterion. But if the angle is right (or obtuse), or if it is opposite the longer of the two sides, there is only one triangle.
Practice
, , . Find in degrees.
We know , and , where is a positive integer. For how many values of are there exactly two (non-congruent) triangles that fit?
In , , , and is the median to side . If the length of is an integer, how many values can it take?
In , , and the points , lie on side with . Prove that .