Concept stop · What is it?

A Map of Equations

In the Chinese book: 方程知识图

The whole volume in one picture: every equation reduces to ax = b.

📖 Chapter 18 of 《方程与方程组》

Before this stop, visit:Word Problems with Equations (Skill)

Hands first, words secondClick a box and watch the route it takes, step by step, down to the terminus at the bottom. The label on each arrow is the move for that step.

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Try this

  1. Click “Fractional eq.”, then “Radical eq.”. Where do their routes join? Apart from the move, what extra line is written on their arrows?
  2. Click “Higher degree” and “Quad. system”. Which stop comes next for each?
  3. On the whole map, how many routes reach the terminus without passing through “Quadratic eq.”?
  4. Click the small stops in dashed boxes (“Complete sq.”, “Discriminant”, “Vieta”, “Integer roots”…). They are not on the main routes. Whom does each of them help?
  5. Under every card there is a button to the matching chapter. Which chapter have you not visited yet?

This volume covered many kinds of equations, but only one method, called reduction: if you cannot solve it, turn it into something you can solve.

  • unknown in a denominator polynomial equation
  • unknown under a square root rational equation
  • high degree low degree
  • many unknowns fewer unknowns

Predict first

Which of these four moves can add solutions to an equation (letting in extraneous roots)?

Choose an answer first; then you can see the result.

Why

Follow one problem along the whole route. With every step, the equation changes into a simpler kind.

Example: solve √(x+3) = x − 3

Step 1 / 5
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  1. Recognize the kind

    The unknown is under a square root, so this is a radical equation. The root is already alone on the left.

Three moves take you down: clearing denominators or squaring, reducing the degree, and eliminating. One habit brings you back: checking.

Remove one condition

Break it

Counterexample lab: remove one condition

Conclusion: every number you found is a solution of the original equation

Do it properly: solve . Multiplying both sides by gives , so . Check: at the denominator , so it is an extraneous root, and the original equation has no solution.

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Practice

Four problems, four kinds. Find each one on the map first, then get to work.

Exercise 1Basic

Solve .

Exercise 2Advanced

Solve . (Give all the real solutions.)

Exercise 3Advanced

Solve .

Exercise 4Challenge

Solve . (If there is a solution, enter it. If there is none, type “no solution”.)

Mistake Museum · Exhibits from this stop

Before you leave, look at the traps other people fell into here.See every exhibit in the museum →

Exhibit

Forgetting to go back and check after simplifying

The wrong step: Solve : multiply both sides by to get , so .
What went wrong? Think first, then open

Diagnosis Multiplying both sides by leaves the solutions unchanged only if . The answer is exactly , which makes the denominators of the original equation , so the original equation means nothing there.

The right step: Substitute into the denominator to check: , so it is an extraneous root and is rejected. The original equation has no solution.

“After clearing denominators or squaring both sides, you must go back and check the roots in the original equation”