Skill stop · How is this move done?

Word Problems with Equations

In the Chinese book: 列方程解应用题

Draw the story as a distance–time graph. Where the lines cross is the solution.

📖 Chapter 17 of 《方程与方程组》

Before this stop, visit:Integer Roots of Quadratic Equations (Method)

WorkbenchDrag the time slider (or click “Go”) until A and B meet. At the moment they meet, what are the two lines on the graph below doing?

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What this move does

The hard part of a word problem is the “translation”: turning a paragraph into an equation. The translation needs just one thing, an equal relationship: say the same quantity in two different ways and put an equals sign between them.

In journey problems, the two most useful sentences are:

  • Meeting (walking toward each other): the sum of the distances the two travel = the distance between them at the start.
  • Catching up (walking the same way): the difference of the distances the two travel = the distance between them at the start.

Draw each person's position as a line on a distance–time graph, and both sentences say the same thing: the two lines cross. Solving a word problem with an equation takes four steps:

  1. Choose: pick one unknown quantity and call it . Say what its unit is and where it is measured from.
  2. Write: express all the other quantities in terms of , and use the equal relationship to write an equation.
  3. Solve the equation.
  4. Check and answer: check that the solution fits the story, then answer the question that was actually asked.

Predict first

B leaves school traveling at km per hour. hour later, A leaves school to chase B at km per hour. How many hours after A leaves does A catch B?

hours
Choose an answer first; then you can see the result.

Work through one

Example. Towns P and Q are km apart. A truck (T) drives from P toward Q at km per hour. hour later, a car (C) drives from Q toward P at km per hour. How many hours after the car leaves do they meet?

Example: when do the truck and the car meet?

Step 1 / 6
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  1. Choose

    The question asks “how many hours after the car leaves”, so call that . The time on the graph is measured from when the truck leaves, so they meet at .

Same graph, different story

A job takes A days working alone, and B days working alone. How many days does it take them working together?

Think of the whole job as parts: A does parts a day and B does part a day. Let A work upward from part and B work downward from part . The moment they “meet”, the job is exactly finished.

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A work problem is a meeting problem: , so .

Let them finish together in days. Written with fractions, this is

“Work done = rate × time” is the same relationship as “distance = speed × time”. Mixture problems (amount of salt = amount of solution × concentration) and money problems (total cost = unit price × quantity) look the same too: find the “this × that = the other” relationship, then look for the quantity that stays the same before and after.

When it fails

Break it

Counterexample lab: remove one condition

Conclusion: going the same way, the one behind is sure to catch the one in front

B is km ahead of A and travels at km per hour; A travels at km per hour. A closes the gap by km each hour and catches B in hours.

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Practice

Exercise 1Basic

Two towns are km apart. Cars A and B leave the two towns at the same time and drive toward each other, A at km per hour and B at km per hour. After how many hours do they meet?

Exercise 2Basic

A younger brother walks at meters per minute and sets off minutes early. His older brother walks at meters per minute and follows the same road from the same place. How many minutes after the older brother sets off does he catch up?

Exercise 3Advanced

A job takes A days alone and B days alone. A works alone for days, then the two work together. How many more days does the job take? (You may write a fraction.)

Exercise 4Challenge

Salt water of concentration and of concentration are mixed to make g of salt water of concentration . How many grams of the salt water are needed?

Mistake Museum · Exhibits from this stop

Before you leave, look at the traps other people fell into here.See every exhibit in the museum →

Exhibit

Is the average speed the average of the speeds?

The wrong step: Going there at km per hour and coming back the same way at km per hour, the average speed for the round trip is km/h.
What went wrong? Think first, then open

Diagnosis Average speed is total distance ÷ total time. The return trip is slower, so it takes longer and makes up more of the total time. That pulls the average speed toward .

The right step: Let each way be km. The total time is hours, so the average speed is km/h.

“First ask “total ÷ total”. Do not rush to add the two speeds and divide by 2”

Exhibit

The two clocks are not lined up

The wrong step: The truck leaves hour before the car. Let them meet after hours: .
What went wrong? Think first, then open

Diagnosis The two 's in this equation are not the same length of time: the truck has been driving hour longer than the car. You must first say clearly whose start is measured from.

The right step: Let them meet hours after the car leaves. Then the truck has driven for hours: .

“When you choose the unknown, say exactly from which moment and which point it is measured”

Exhibit

Stopping once you have x

The wrong step: B leaves hour early and A chases. Let B be caught hours after B leaves; solving gives . Answer: A took hours to catch B.
What went wrong? Think first, then open

Diagnosis is how long B has been traveling. A left hour later and traveled for only hours. The equation was solved correctly, but the question was answered wrongly.

The right step: After solving, go back and reread what the question asks: A chased for hours. Then check that the answer makes sense (no negative times, whole numbers of people, …).

“The last step is to answer, not to solve”