In one sentence
Mixed circle problems all look different, but there are only a few weapons to choose from. When you read the problem, don't rush to calculate: first translate the conditions in the figure into one of these three kinds of invariant:
- Equal angles: inscribed angles on the same arc, tangent–chord angles, exterior angles of a cyclic quadrilateral.
- Equal products: two lines through a point meeting the circle give .
- Equal lengths: radii, tangent lengths, the two halves of a chord cut by a perpendicular diameter.
When you see this, think of that
Step 1 / 6- You see a diameter
Think right angle: an inscribed angle on a diameter is . Conversely, when you see a right angle on a circle, look for a diameter.
Predict first
is a diameter of a circle, chord at , and . How long is chord ?
The answer is . There are at least three ways to solve it, each using a different “invariant”: see Stop 1 below.
Stop 1 · One problem, three weapons
One problem, several solutions
is a diameter of a circle, chord at , and . Find the length of .
Equal products: intersecting chords
Chords and meet at , so .
The diameter is perpendicular to chord , so by the perpendicular-diameter theorem . Hence , and .
CostOne line, once you see that H is where two chords cross.
Equal lengths: radius and distance to the chord
The diameter is , so the radius is , and the distance from the center to is .
In right triangle , , so .
CostYou need the radius first, but no power of a point at all.
Equal angles: the right angle on a diameter
Join and . is a diameter, so .
and are both complementary to , so they are equal. Then , which gives , and .
CostOne similarity, and you pick up a useful result on the way.
Stop 2 · Angles: first sort out where the vertex is
When the central angle is , the inscribed angle on the major arc is and on the minor arc it is . Whenever a problem talks about “the inscribed angle on a chord”, or doesn't say which arc the point is on, you must give both answers.
Stop 3 · Concyclic points: draw the invisible circle
The angle condition and the length condition say the same thing. When a problem gives you angles but asks for a product of lengths (or the other way round), the bridge in between is often “four concyclic points”.
Practice
A circle has radius , chord , and is a point on the circle other than and . What can be, in degrees? (List every possibility, separated by commas.)
is tangent to a circle at , and . A secant through meets the circle at then , with . Find the length of chord .
Quadrilateral is inscribed in a circle, and its diagonals and meet at . , , and . Find the length of .
Two circles meet at and . A line through meets the two circles again at and , and a line through meets them again at and ( and are on the first circle, and on the second; is between and , and is between and ). Prove that .