In one sentence
When an expression has several letters, problems usually call “the unknown” and the others “parameters”. But that is only a name: the expression itself does not know which letter is the unknown. Pick the letter with the lowest degree as the main variable, treat every other letter as part of the coefficients, and the problem often becomes simple at once.
Example: factor x³ − ax² + 2x − 2a
Step 1 / 4- The usual view
Ordered by powers of : a cubic, with mixed into the coefficients. No ready-made formula applies.
Predict first
has degree four in . What is its degree in ?
The only terms containing are and , so in it is a quadratic: .
For quadratics we have the discriminant and the quadratic formula. The widget below does the work for you: the discriminant is , a perfect square, so the expression factors.
Stop 1 · Factoring quadratics in two variables (Vol. 1)
When both letters appear squared, pick either one as the main variable and the other goes into the coefficients: it is the cross method, with expressions as coefficients.
Example: factor x² + 3xy + 2y² + 4x + 5y + 3
Step 1 / 4- Make x the main variable
Group the terms into three piles: those with , those with , and those with no .
Stop 2 · Equations with letter coefficients (Vol. 2)
“Holds for every value of ” really says: with as the main variable, you have an identity in . A linear expression equals for every only if and .
Example: for every value of m, the line (m+1)x + (m−2)y − 3m = 0 passes through the same point. Find it
Step 1 / 5- What is changing?
can take any value, while the point we want is fixed. So the real “variable” here is .
Stop 3 · Integer roots of quadratic equations (Vol. 2)
The equation is quadratic in , but linear in the parameter . So solve for , and let divisibility pick out .
Example: find all integers a for which x² − ax + a + 3 = 0 has an integer root
Step 1 / 5- The usual view
With as the main variable, the discriminant has to be a perfect square. That works, but it is the long way round.
Stop 4 · Finding a range (Vol. 2 · the discriminant)
To find how large can be, you actually treat as a known coefficient and make the other letter the main variable: whether can take a certain value depends on whether the equation in has a real root.
Example: real numbers x and y satisfy x² + xy + y² = 3. Find the maximum value of x
Step 1 / 4- Make y the main variable
Treat as a coefficient. This is a quadratic equation in .
Practice
For every value of , the line passes through the same point. What is the sum of that point's - and -coordinates?
Find all integers for which the equation (in ) has an integer root. (Separate them with a comma.)
Real numbers and satisfy . Find the maximum value of .